# Steam Turbine Calculator watch tutorial view guide

### Calculates the energy generated or steam outlet conditions for a steam turbine.

Allowed Range / Limits | |
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Minimum | |

Maximum | |

Examples: | Mouse Over |
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Solve for Outlet Properties | Solve for Isentropic Efficiency |

### Calculation Details and Assumptions below

## Inlet Steam |
Mass Flow | 18.2 klb/hr | |
---|---|---|---|

Pressure | 635.7 psig | Sp. Enthalpy | 1,385.1 btu/lbm |

Temperature | 406.6 °C | Sp. Entropy | 6.732 kJ/kg/K |

Phase | Gas | Energy Flow | 26,596 |

## Outlet Steam |
Mass Flow | 18.2 klb/hr | |
---|---|---|---|

Pressure | 364.9 psig | Sp. Enthalpy | 1,343.7 btu/lbm |

Temperature | 350.4 °C | Sp. Entropy | 6.820 kJ/kg/K |

Phase | Gas | Energy Flow | 25,801 |

Isentropic Efficiency | 64.3 % |
---|---|

Energy Out | 795 |

Generator Efficiency | 98.3 % |

Power Out | 217.1 kW |

## Calculation Details

### Step 1: Determine Inlet Properties

Using the Steam Property Calculator, properties are determined using Inlet Pressure and the selected second parameter (Temperature, Specific Enthalpy, Specific Entropy, or Quality). The Specific Enthalpy is then multiplied by the Mass Flow to get the Energy Flow:`Pressure`= 635.7 psig`Temperature`= 406.6 °C- [Steam Property Calculator] =>
`Specific Enthalpy`= 1,385.1 btu/lbm

`Inlet Energy Flow`=`Specific Enthalpy`*`Mass Flow`

[`Inlet Energy Flow`= 26,596 = 1,385.1 btu/lbm * 18.2 klb/hr ]

### Step 2: Calculate Ideal Outlet Properties (Inlet Entropy equals Outlet Entropy)

`Pressure`= 364.9 psig`Specific Entropy`= 6.732 kJ/kg/K- [Steam Property Calculator] =>
`Specific Enthalpy`= 1,320.7 btu/lbm

### Step 3: If solve for 'Isentropic Efficiency', Determine Outlet Properties

Using the outlet specific enthalpy, calculate the isentropic efficiency:`Isentropic Efficiency`= (`Inlet Specific Enthalpy`-`Outlet Specific Enthalpy`) / (`Inlet Specific Enthalpy`-`IDEAL Outlet Specific Enthalpy`)

### Step 3: If solve for 'Outlet Properties', Determine Outlet Specific Enthalpy

`Isentropic Efficiency`= (`Inlet Specific Enthalpy`-`Outlet Specific Enthalpy`) / (`Inlet Specific Enthalpy`-`IDEAL Outlet Specific Enthalpy`)`Isentropic Efficiency`* (`Inlet Specific Enthalpy`-`IDEAL Outlet Specific Enthalpy`) = (`Inlet Specific Enthalpy`-`Outlet Specific Enthalpy`)`Outlet Specific Enthalpy`=`Inlet Specific Enthalpy`-`Isentropic Efficiency`* (`Inlet Specific Enthalpy`-`IDEAL Outlet Specific Enthalpy`)

[`Outlet Specific Enthalpy`= 1,343.7 btu/lbm = 1,385.1 btu/lbm - 64.30 % * (1,385.1 btu/lbm - 1,320.7 btu/lbm)]

`Pressure`= 364.9 psig`Specific Enthalpy`= 1,343.7 btu/lbm- [Steam Property Calculator] =>
`Temperature`= 350.4 °C

### Step 4: Calculate Steam Turbine Energy Out and Generation (Power Out)

`Energy Out`= (`Inlet Specific Enthalpy`-`Outlet Specific Enthalpy`) *`Mass Flow`

[`Energy Out`= 795 = (1,385.1 btu/lbm - 1,343.7 btu/lbm) * 18.2 klb/hr]

`Power Out`=`Energy Out`*`Generator Efficiency`

[`Power Out`= 217.1 kW = 795 * 98.30 %]

## Assumptions

- Inlet Mass Flows equal Outlet Mass Flow.